PYTHON : OSError [Errno 22] invalid argument when use open() in Python

PYTHON : OSError [Errno 22] invalid argument when use open() in Python

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OSError: [Errno 22] Invalid argument: ' "GET /po HTTP/1.1" 500 68771while using open() in Python
OSError: [Errno 22] Invalid argument: ' "GET /po HTTP/1.1" 500 68771while using open() in Python
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